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Calculate the degree of hydrolysis of 0.1 M solution of sodium acetate at `298 K : K_(a) = 1.8 xx 10^(-5)`. |
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Answer» (I). Calculation of hydrolysis constant `(K_(h)).` Since sodium acetate is a salt of strong base and weak acid `K_(h) =(K_(w))/(K_(a)) =(1.0xx10^(-14))/(1.8xx10^(-5)) =5.5 xx 10^(-10)` (II). Calculation of degree of hydrolysis (h). `K_(h) =5.5 xx 10^(-10) , C =0.1 M` Degree of hydrolysis (h)`=sqrt((K_(h))/(C))=sqrt((5.5xx10^(-10))/(0.1))=(55xx10^(-10))^(1//2) =7.42 xx10^(-5).` |
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