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Calculate the degree of dissociation of pcl5 if the vapour density at the give temperature is 70. |
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Answer» Answer: The molar mass PCl 3
is 137.33 g/mol The molar mass CL 2
is 70.6 g/mol INITIAL molar mass 2× initial vapour density =2×104.16=208.32g/mol Final molar mass =2× final vapour density =2×62=124g/mol 5
present initially, X mole dissociates to form x mole of PCl 3
and x mole of Cl 2
The molar mass of final mixture =124= 1−x+x+x 208.32(1−x)+137.33x+70.6x
124= 1+x 208.32(1−x)+(137.33+70.6)x
124= 1+x 208.32(1−x+x)
124= 1+x 208.32
1+x= 124 208.32
=1.68 x=1.68−1=0.68 The degree of dissociation of PCl 5
at 230 ∘ C is 1 0.68
=0.68 or 68 %. Explanation: 68/ |
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