1.

Calculate the de-Brogle wavelength of an electron whose kinetic energy is same as 60 Ke V X-rays

Answer»

`0.05 m`
`0.05 Å`
`0.5 Å`
`2 Å`

Solution :`KE_(e ) = 60 KeV`
`KE_(e ) = 60 xx 10^(3)` eVolt `= q DELTA V` (for electron, q = e)
`Delta V = 60 xx 10^(3)` VOLT
`lambda_(e ) = SQRT((150)/(60 xx 10^(3))) Å = sqrt((1)/(400)) Å = (1)/(20) Å = 0.05 Å`


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