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Calculate the cryoscopic constant in `(K Kg mol^(-1))` of cyclohexane. Given that its heat of fusion is `2630J//mol` and it freezing point is `6.6^(@)C`.A. `20.76`B. `28.33`C. `23.15`D. `18.15` |
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Answer» Correct Answer - A `K_(f)=(M_("solvent").RT_(f)^(2))/(1000.DeltaH_("Fusion"))` `=(84xx8.314xx(279.60)^(2))/(1000xx2630)=20.76` |
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