1.

Calculate the concentration of OH^(-) in a fruit juice which contains 2xx10^(-3)M, H_(3)O^(+) ion. Identify the nature of the solution.

Answer»

Solution :`"Given that "H_(3)O^(+)=2XX10^(-3)M`
`K_(W)=[H_(3)O^(+)][OH^(-)]`
`therefore [OH^(-)]=(K_(w))/([H_(3)O^(+)])=(1xx10^(-14))/(2xx10^(-3))=0.5xx10^(-11)M`
`2xx10^(-3) GT gt 0.5 xx 10^(-11)`
i.e., `[H_(3)O^(+)] gt gt [OH^(-)]`, hence the juice is acidic in nature


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