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Calculate the concentration of OH^- in a fruit juice which contains 2 times 10^-3 M,H_3O^(+) ion. Identify the nature of the solution. |
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Answer» Solution :GIVE that `H_3O^+=2 times 10^-3 M` `K_w=[H_3O^+][OH^-]` `therefore [OH^-]=K_w/([H_3O^+])=(1 times 10^-14)/(2 times 10^-3)=0.5 times 10^-11 M` `2 times 10^-3 GT gt 0.5 times 10^-11` i.e., `[H_3O^+] lt lt [OH^-]` , HENCE the juice is acidic in nature. |
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