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Calculate the coefficient of correlation by Karl Pearson’s Method from thefollowing data: X 6 2 10 4 8 12Y 9 11 14 8 7 5 |
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Answer» Answer: The sales in: The sales in:(i) 2002 was Rs.4 crores and (ii) 2006 was Rs.8 crores The sales in:(i) 2002 was Rs.4 crores and (ii) 2006 was Rs.8 crores(B) The sales in: The sales in:(i) 2002 was Rs.4 crores and (ii) 2006 was Rs.8 crores(b) The sales in:(i) 2003 was Rs.7 crores and (ii) 2005 was Rs.10 crores. The sales in:(i) 2002 was Rs.4 crores and (ii) 2006 was Rs.8 crores(b) The sales in:(i) 2003 was Rs.7 crores and (ii) 2005 was Rs.10 crores.(C) The difference of sales in 2002 and 2006 = Rs.8 crores–Rs.4 crores= Rs.4 crores The sales in:(i) 2002 was Rs.4 crores and (ii) 2006 was Rs.8 crores(b) The sales in:(i) 2003 was Rs.7 crores and (ii) 2005 was Rs.10 crores.(c) The difference of sales in 2002 and 2006 = Rs.8 crores–Rs.4 crores= Rs.4 crores(d)In the YEAR 2005, there was the greatest difference between the sales and COMPARED to its previous year, which is (Rs. 10crores –Rs. 6crores) = Rs. 4crores. |
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