Calculate the charges of an iron particle of mass 224 mg if 0.01% of t

1.	Calculate the charges of an iron particle of mass 224 mg if 0.01% of the electrons are removed from it.
Answer» Given here: Atomic mass of iron = 56 now, 1 mole of iron contains 56 g of iron. no. of moles in 224 g iron = n= 224/56 = 4 Now, Total number of electrons or protons in 4 moles of iron = n × avagadro number = 4 × 6.032 × 10²³ 0.01 % of 4 × 6.032 × 10²³ = a = (0.01/100) × 4 × 6.032 × 10²³ = 2.41×10²⁰ Now, defecient negative charge = a × charge on electron = 2.41×10²⁰ × 1.602 × 10^-19= 38.6 C Positive charge acquired by 224g iron = defecient negative charge = 38.6 C

Calculate the charges of an iron particle of mass 224 mg if 0.01% of the electrons are removed from it.

Answer»

Given here: Atomic mass of iron = 56
now, 1 mole of iron contains 56 g of iron.
no. of moles in 224 g iron = n= 224/56 = 4
Now,
Total number of electrons or protons in 4 moles of iron = n × avagadro number = 4 × 6.032 × 10²³
0.01 % of 4 × 6.032 × 10²³ = a = (0.01/100) × 4 × 6.032 × 10²³ = 2.41×10²⁰

Now, defecient negative charge = a × charge on electron

= 2.41×10²⁰ × 1.602 × 10^-19= 38.6 C

Positive charge acquired by 224g iron = defecient negative charge = 38.6 C

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Calculate the charges of an iron particle of mass 224 mg if 0.01% of the electrons are removed from it.

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