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| 1. |
calculate the change in kinetic energy if it's velocity reduced by one third of the initial velocity? |
| Answer» CHANGE is (5/9)K₁ ; decreased by (5/9) of the initialExplanation: General method:As we know, K ∝ v² ; LET K₁ = xv² , where x is a constantIf v is reduced by 1/3, NEW VELOCITY is ⇒ v - v/3 ⇒ 2v/3Therefore, K₂ = x(2v/3)² = (4/9)xv² K₂ = (4/9) K₁Hence, the change in K is ΔK = K₂ - K₁ = (4/9)K₁ - K₁ = - (5/9)K₁This means, K is decreased by 5/9 . | |