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Calculate the centripetal acceleration of moon towards the earth |
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Answer» Solution :The centripetal acceleration is given by `a = (v^2)/(r )` .This expression EXPLICITLY depends on Moon.s speed which is nontrivial. We can work with the formula `omega^2 R_m = a_m` `a_m`is centripetal acceleration of the Moon due to Earth.s GRAVITY. `omega `is angular VELOCITY `R_m`is the distance between Earth and the Moon, which is 60 times the radius of the Earth. `R_m = 60 R = 60 xx 6.4 xx 10^6 = 384 xx 10^6 m` As we know the angular velocity `omega = (2pi)/(T)` and `T = 27. 3 days = 27.3 xx 24 xx 60 xx 60 sec= 2.358 xx 10^6 sec ` By substituting these values in the formula for acceleration `a_m = ((4pi^2) (384 xx 10^6) )/((2.358 xx 10^6)^2) = 0.00272 MS^(-2)` The centripetal acceleration of Moon towards the Earth is` 0.00272 ms^(-2)` |
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