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Calculate the cell potential for Cu plate kept in 0.2 M CuSO_(4) solution.[E_(Cu^(+)|Cu^(2+))^(Theta)=0.34V] |
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Answer» SOLUTION :According to Nernst equation the potential of this electrode, `E_(Cu^(2+)|Cu)=E_(Cu^(2+)|Cu)^(THETA)-(0.059)/(n)"LOG"(1)/([Cu^(2+)])` `=0.34V-0.0295("log"(1)/(0.2))` `=0.34V-(0.0295)(log5.0)` `=0.34-(0.0295)(0.6990)` `=0.34-0.0206` `=0.3194V` |
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