1.

Calculate the bond enthalpy of Xe-F bond as given in the equation, XeF_(4)(g)toXe^(+)(g)+F^(-)(g)+F_(2)(g)+F_(g),Delta_(r)H=292" kcal "mol^(-1) Ionisation energy of Xe=279 kcal/mol bond energy (F-F)=38 kcal/mol Electron affinity of F=85 kcal/mol

Answer»

8.5 kcal/MOL
34 kcal/mol
24 kcal/mol
none of these

Solution :`Delta_(r)H=`Heat supplied-heat EVOLVED
`292=(4x+279)-(38+85)impliesx=34` kcal `mol^(-1)`


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