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Calculate the boiling point sollution when 2 g of Na_(2)SO_(4) (M=142 g mol^(-1)) was dissoved in 50 g of water assuming that NaSO_(4) undergoes complete ionization (K_(b) for water = 0.52 K kg mol^(-1)) |
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Answer» `Na_(2)SO_(4)" DISSOCIATES in aqueous solution as ":` `Na_(2)SO_(4)(s)overset(("aq"))to2Na^(+)("aq")+SO_(4)^(2-)("aq")` `i=3, W_(B)==2g, M_(B)=142"g MOL"^(-1), W_(A)=50g=0.050 kg` `K_(b)=0.52" K kg mol"^(-1)` `DeltaT_(b)=ixxK_(b)xxm=(xx(0.52" K kg mol"^(-1))xx(2g))/((142" g mol"^(-1))xx(0.050" kg "))=0.44 K` Step II. `"Calculation of boilling point of solution" (T_(b))` `T_(b)=T_(b)^(@)+DeltaT_(b)=373 K+0.44 K=373.44 K` |
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