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Calculate the boiling point of bromine from the following data : DeltaH^(0) and DeltaS^(0) values of Br_(2)(l) to Br_(2)(g) are 30.91 kJ/"mole" and 93.2 J/"mol". K respectively. Assume that DeltaH and DeltaS do not vary with temperature. |
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Answer» Solution :Consider the process : `Br_(2)(L) to Br_(2)(G)` The b.p. of a LIQUID is the temperature at which the liquid and the pure gas coexist at equilibrium at 1 atm `:. DeltaG=0` As it is given that `DELTAH` and `DeltaS` do not change with temperture `DeltaH=DeltaH^(@)=30.91kJ` `DeltaS=DeltaS^(@)=93.2J//K=0.0932kJ//K` We have, `DeltaG=DeltaH-TDeltaS=0` `:.T=(DeltaH)/(DeltaS)=(30.91)/(0.0932)=331.6K` This is the temperature at which the SYSTEM is in equilibrium that is the b.p. of bromine. |
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