1.

Calculate the binding energy of an alpha particle given its mass to be 4.00151 u.

Answer»

Data : M = 4.00151 u, = 1.00728 u, 

mn = 1.00866 u, 1 u = 931.5 MeV/c2 

The binding energy of an alpha particle

(Zmp + Nn - M)c

=(2mp + 2mn - M)c

= [(2)(1.00728u) + 2(1.00866 u) – 4.00151 u]c2

= (2.01456 + 2.01732 – 4.00151)(931.5) MeV 

= 28.289655 MeV 

= 28.289655 × 106 eV × 1.602 × 10-19

= 4.532002731 × 10-12 J



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