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Calculate the average volume available to a molecule in a sample of nitrogen gas at STP. What is the average distance between neighbouring molecules if nitrogen molecules are spherical in nature ? |
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Answer» SOLUTION :`6.023 xx10^(23)` molecules of `N_(2)` occupy `22400 cm^(3)` `THEREFORE` one molecules of `N_(2)` occupies `=(22400)/(6.023xx10^(23))cm^(3)` or volume of one molecule of `N_(2)=3.72xx10^(-20) cm^(3)` Also, the average distance between TWO molecules =2r and `(4)/(3) pi r^(3)=3.72xx10^(-20)` `therefore r^(3) =(3.72xx10^(-20)xx3xx7)/(4xx22)` `therefore r=20.7xx10^(-8) cm` Thus, average distance `=2xx20.7xx10^(-8)` `=41.4xx10^(-8) cm` |
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