1.

Calculate the atomic mass (average) of chlorine using the following data : {:(,""%"Natural Adundance","Molar mass"),(.^(35)Cl,"75.77","34.9689"),(.^(37)Cl,"24.23","36.9659"):}

Answer»

SOLUTION :`"FRACTIONAL abundance of ".^(35)Cl=0.7577," Molar MASS "=34.9689`
`"Fractional abundance of ".^(37)Cl=" 0.2423. Molar mass "=36.9659`
`therefore"Average atomic mass "=(0.7577)+(34.9689 AMU)+(0.2423)(36.9659amu)`
`=26.4959+8.9568= 34.4527`


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