Calculate the angular speeds of the second, minute and hour hands of a

1.	Calculate the angular speeds of the second, minute and hour hands of a 12 hour dial clock.
Answer» Solution :(1) `omega` of the second that `=(2pi)/(T)=(2xx3.142)/(60)=1.047xx10^(-1)rads^(-1)` (2) `omega` of the minute hand `=(2xx3.142)/(60xx60)=1.745xx10^(-3)rads^(-1)` (3)`omega` of the hour hand=`(2xx3.142)/(12x3600)=1.454xx10^(-4)RAD^(-1)`

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