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Calculate the angle of (a) 1^(@) (degree) (b) 1' (minute of arc or arcmin) and ("c") 1" (second of arc or arc second ) in radians. Use 360^(@) = 2pi rad, 1^(@)=60' and 1'=60". |
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Answer» SOLUTION :(a)We know that, `180^(@)= PI` rad then `1^(@)=(?)` `:.1^(@)=(pi)/(180)=(3.412)/(180)` `:.1^(@)=0.01745` `:.1^(@)~~1.745xx10^(-2)` rad (b) We know that, `60.(min)=1^(@)` and `1^(@)=1.745xx10^(-2)` rad `:.60.=1.745xx10^(-2)` rad `:. 60.=1.745xx10^(-2)` and then `1.=(?)` `1=(1.745xx10^(-2))/(60)=0.02908xx10^(-2)` `:.1=2.91xx10^(-4)` rad We know that, `60..(sec)=1.(min)` `and 1.(min)=2.908xx10^(-4)` rad `:. 60..=2.908xx10^(-4)` rad then `1,,=(?)` `I..=(2.908xx10^(-4))/(60)=0.048466xx10^(-4)` `:.1..~~4.85xx10^(-6)` rad |
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