Calculate the amount of oxalic acid required to obtain 0.05 ml of semi

1.	Calculate the amount of oxalic acid required to obtain 0.05 ml of semimolar solution? Given molarity 0.5 M
Answer» VOLUME of solution REQUIRED= 0.05 ml => 0.05/1000 litres => 0.00005 litres molarity = 0.5 M let number of moles of H2C2O4 required be x. molarity = (moles of solute)/itres of solution 0.5=x/0.00005 x= 0.000025 moles of Oxalic ACID Molar mass of H2C2O4 = 2X1 + 2X12 + 4X16 => 90 grams per mole. So, mass of H2C2O4 required = 90 X 0.000025 => 0.00225 grams So, 0.00225 grams of anhydrous oxalic acid will be required. Please mark as brainliest, if this was helpful.

Calculate the amount of oxalic acid required to obtain 0.05 ml of semimolar solution? Given molarity 0.5 M

Answer»

VOLUME of solution REQUIRED= 0.05 ml => 0.05/1000 litres => 0.00005 litres

molarity = 0.5 M

let number of moles of H2C2O4 required be x.

molarity = (moles of solute)/itres of solution

0.5=x/0.00005

x= 0.000025 moles of Oxalic ACID

Molar mass of H2C2O4 = 2X1 + 2X12 + 4X16 => 90 grams per mole.

So, mass of H2C2O4 required = 90 X 0.000025 => 0.00225 grams

So, 0.00225 grams of anhydrous oxalic acid will be required.

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