1.

Calculate the amount of limen, Ca(OH)_(2), required to remove hardness of 50,000 litres of well water which has been found to contain 1.62 g of calcium bicarbonate per 10 litre.

Answer»

Solution :(i) Calculation of total `Ca(HCO_(3))_(2)` present
10 L of water contains `Ca(HCO_(3))_(2)=1.62 G`
`therefore 50, 000 L` of water will contain `Ca(HCO_(3))_(2)=(1.62)/(10)xx50000 g=8100 g`
(ii) Calculation of lime REQUIRED. The BALANCED EQUATION for the reaction involved is :
`{:(""Ca(HCO_(3))_(2),+,""Ca(OH)_(2),rarr,2CaCO_(3)+2H_(2)O),("1 mole",,"1 mole",,),(40+(1+12+48)xx2=162 g,,40+(16+1)xx2=74 g,,):}`
`162 g Ca(HCO_(3))_(2)` required lime = 74 g
`therefore 8100g Ca(HCO_(3))_(2)` will required lime `=(74)/(162)xx8100 g=3700 g = 3.7 kg`


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