Calculate the amount of KCL which must be added to 1kg of water so the freezing point is depressed by 2k

Calculate the amount of KCL which must be added to 1kg of water so the

1.	Calculate the amount of KCL which must be added to 1kg of water so the freezing point is depressed by 2k
Answer» $change\ in\ freezing\ point,\ \Delta T_f=k_f \times m\\ \\ \Rightarrow m= \frac{\Delta T_f}{k_f} \\ \\ \Rightarrow m= \frac{2}{1.86} =1.075\ mole/kg\\ \\m= \frac{no.\ of\ moles\ of\ solute}{mass\ of\ solvent}= \frac{n}{mass\ of\ water} \\ \\ \Rightarrow 1.075= \frac{n}{1} \\ \\ \Rightarrow n=1.075\ moles\\ \\ \therefore amount\ of\ KCl\ needed\ is\ 1.075\ mole.$