Calculate the amount of heat required to convert 1.00 kg of ice at −10∘C into steam at 100∘C at normal pressure. (Sice=2100 J kg−1K−1, Swater=4200 J kg−1K−1 Lfice=3.36×105 J kg−1 Lvwater=2.25×106 J kg−1)

Calculate the amount of heat required to convert 1.00 kg of ice at −

1.	Calculate the amount of heat required to convert 1.00 kg of ice at −10∘C into steam at 100∘C at normal pressure. (Sice=2100 J kg−1K−1, Swater=4200 J kg−1K−1 Lfice=3.36×105 J kg−1 Lvwater=2.25×106 J kg−1)
Answer» Calculate the amount of heat required to convert 1.00 kg of ice at $- 10^{\circ}$ C into steam at $100^{\circ}$ C at normal pressure. $(S_{i c e} = 2100 J k g^{- 1} K^{- 1}, S_{w a t e r} = 4200 J k g^{- 1} K^{- 1} L f_{i c e} = 3.36 \times 10^{5} J k g^{- 1} L v_{w a t e r} = 2.25 \times 10^{6} J k g^{- 1})$

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Calculate the amount of heat required to convert 1.00 kg of ice at −10∘C into steam at 100∘C at normal pressure. (Sice=2100 J kg−1K−1, Swater=4200 J kg−1K−1 Lfice=3.36×105 J kg−1 Lvwater=2.25×106 J kg−1)

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