Calculate the amount of heat required to convert 1.00 kg of ice at -10

1.	Calculate the amount of heat required to convert 1.00 kg of ice at -10°C at normal pressure to steam at 100°C. The specific heat capacity of ice=2100 Jkg−1K−1 Latent heat of fusion of ice=3.36×105 Jkg−1 The specific heat capacity of water=4200 Jkg−1K−1 Latent heat of vaporization of water=2.25×106 Jkg−1
Answer» $Calculate the amount of heat required to convert 1.00 kg of ice at -10°C$ $at normal pressure to steam at 100°C.$ $The specific heat capacity of ice = 2100 J k g^{- 1} K^{- 1}$ $Latent heat of fusion of ice = 3.36 \times 10^{5} J k g^{- 1}$ $The specific heat capacity of water = 4200 J k g^{- 1} K^{- 1}$ $Latent heat of vaporization of water = 2.25 \times 10^{6} J k g - 1$

Calculate the amount of heat required to convert 1.00 kg of ice at -10°C at normal pressure to steam at 100°C. The specific heat capacity of ice=2100 Jkg−1K−1 Latent heat of fusion of ice=3.36×105 Jkg−1 The specific heat capacity of water=4200 Jkg−1K−1 Latent heat of vaporization of water=2.25×106 Jkg−1

Answer»

$Calculate the amount of heat required to convert 1.00 kg of ice at -10°C$
$at normal pressure to steam at 100°C.$

$The specific heat capacity of ice = 2100 J k g^{- 1} K^{- 1}$

$Latent heat of fusion of ice = 3.36 \times 10^{5} J k g^{- 1}$

$The specific heat capacity of water = 4200 J k g^{- 1} K^{- 1}$

$Latent heat of vaporization of water = 2.25 \times 10^{6} J k g - 1$