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calculate the amount of energy released when radioactive undergoes fusion and results in a mass defect of 2kg. |
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Answer» ONG>Answer:
speed of light in vacuum(c)=3×10^8 m/S
Energy released=mc^2=2×3×10^8 J
=6×10^8 Jmass defect(m)=2kg
speed of light in vacuum(c)=3×10^8 m/S
Energy released=mc^2=2×3×10^8 J
=6×10^8 J |
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