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Calculate the amount of energy released in ergs, calories and in joules when 0.001 kg of mass disappears. [Given, Velocity of light =3xx10^(8)m s^(-1)] |
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Answer» SOLUTION :According to Einstein equation , `E=mc^(2)` `m=0.001kg=1XX10^(-3)kg, c=3XX10^(8)ms^(-1)` `E=(1xx10^(-3))(3xx10^(8))^(2)=9xx10^(13)J` 1J`=10^(7)"erg"=0.24` cal `9xx10^(13)J=9xx10^(13)xx10^(7)"erg"=9xx10^(13)xx0.24` cal `=9xx10^(20)` erg `=2.16xx10^(13)` cal. |
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