1.

Calculate the amount of carbon dioxide that could be produced when (i) 1 mole of carbon is burnt in air. (ii) 1 mole of carbon is burnt in 16 g of dioxygen. (iii) 2 moles of carbon are burnt in 16 g of dioxygen.

Answer»

Solution :The balanced equation for the combustion of carbon in dioxygen/air is
`underset("1 mole")(C(s))""+""underset("(32 g)")underset("1 mole")(O_(2)(g))""rarr""underset("(44 g)")underset("1 mole")(CO_(2)(g))`
(i) In air, combustion is complete. THEREFORE, `CO_(2)` produced from the combustion of 1 mole of carbon = 44 g.
(II) As only 16 g of dioxygen is available, it can combine only with 0.5 mole of carbon, i.e., dioxygen is the limiting REACTANT. Hence, `CO_(2)` produced = 22 g.
(III) Here again, dioxygen is the limiting reactant. 16 g of dioxygen can combine only with 0.5 mole of carbon. `CO_(2)` produced again is equal to 22 g.


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