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Calculate the amount of carbon dioxide gram produced by the reaction 32 gram methane gram and 32 gram of oxygen gram |
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Answer» Answer: Explanation: Converting mass to number of moles: 16g of methane = 1 mole of CH4 as Molecular weight of CH4 is 16 (16 gram/ 16 gram per mole ) So, CH4 + 2O2 → CO2 +2H2O 16 GM + 2* (32 gm) → 80 gm of products (CONSERVATION of mass but not Moles) of 80 gm, one mole of CO2 is equivalent to 44 gm ( as MW= 44 gm/mol) So, 80–44= 36 gm ( 2* 18 gm) of water.......... |
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