1.

Calculate the amount in moles of SO3 formed when 0.36 mol SO2 react with excess O2​

Answer»

0.36 moles of sulphur TRIOXIDE formed Explanation:2SO2 + O2 ---------> 2 SO3 . From this BALANCED CHEMICAL equation it is clear that 2 moles of sulphur dioxide gives 2 moles of sulphur trioxide. So 0.36 mol of sulphur dioxide will give 0.36 mol of sulphur trioxide.



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