Saved Bookmarks
| 1. |
Calculate the accelaration and distance of the body moving with 5m/s which comes to rest after traveling for 6 sec? |
|
Answer» Answer: 0.83333..m2/s Explanation: u=0m/s(as the body starts from REST) t=6s as we KNOW that acceleration (a)=v-u/t so,a=5-0/6 a=5/6m2/s or 0.8333m2/s |
|