Calculate the (a) momentum and (b) de Broglie wavelength of the electr

1.	Calculate the (a) momentum and (b) de Broglie wavelength of the electrons accelerated through a potential difference of 56 V.
Answer» For electron, mass m = 9.1 × 10^–31kg (a) Momentum p = √2mE_k = √2meV = √(2x 9.1 x 10^-31 x 1.6 x 10^-19 x 56) = 4.04 x 10^-24kg ms^-1 (b) de Broglie wavelength λ = h/p = (6.63 x 10^-34/4.14 x 10^-24) = 1.64 × 10^–10 m = 0.164 nm

Calculate the (a) momentum and (b) de Broglie wavelength of the electrons accelerated through a potential difference of 56 V.

Answer»

For electron, mass m = 9.1 × 10^–31kg

(a) Momentum p = √2mE_k = √2meV

= √(2x 9.1 x 10^-31 x 1.6 x 10^-19 x 56) = 4.04 x 10^-24kg ms^-1

(b) de Broglie wavelength λ = h/p = (6.63 x 10^-34/4.14 x 10^-24)

= 1.64 × 10^–10 m = 0.164 nm

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Calculate the (a) momentum and (b) de Broglie wavelength of the electrons accelerated through a potential difference of 56 V.

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