1.

Calculate standard Gibbs free energy for the reaction : Zn+Cu^(2+)toZn^(2+)+Cu,E_("cell")^(@)=1.10V

Answer»

Solution :`E_("cell")^(@)=1.10V`
For the cell reaction,
`Zn+CU^(2+)TOZN^(2+)+Cu`
n=2
`F=96,500C`
`DeltaD^(@)=-nFE_("cell")^(@)`
`=-2xx96500xx1.10`
`=-2123000J`
`=-212.3kJ`


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