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Calculate standard enthalpy of reaction fe2o3+3co=2fe+3co2 from the following data.∆fh°(fe2o3)=-824kj/mol,∆fh°(co)=-110kj/mol,∆fh°(co2)=-393kj/mol |
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Answer» fh° (fe2o3) = -824 kj/mol, ∆fh° (co) = -110 kj/mol, ∆fh° (co2) = -393 kj/molTo FIND:Calculate standard enthalpy of reaction fe2o3+3co=2fe+3co2 from the following data.Solution:From given, we have,∆fh° (fe2o3) = -824 kj/mol, ∆fh° (co) = -110 kj/mol, ∆fh° (co2) = -393 kj/molwe use the formula,∆fh° = [2 ∆fh° (fe) + 3 ∆fh° (co2)] - [1 ∆fh° (fe2o3) + 3 ∆fh° (co)] ∆fh° = [2 (0) + 3 (-393)] - [1 (-824) + 3 (-110)] ∆fh° = [0 - 1179] - [-824 - 330] ∆fh° = - 1179 - [-1154] ∆fh° = - 1179 + 1154∴ ∆fh° = - 25 kJ/molTherefore, the standard enthalpy of reaction fe2o3+3co=2fe+3co2 is - 25 kJ/mol |
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