1.

Calculate spin magnetic momentum of M_((aq))^(+2) ions. (Z=27)

Answer»

3.80BM
3.87BM
0.387BM
38.7BM

Solution :Here, atomic number Z=27
So, for M ions `=[Ar] 3d^(7) 4s^(2)`
So, for `M^(+2)` ions = `[Ar] 3d^(7)`

Here, UNPAIRED ELECTRONS are 3.
`:.` Magnetic momentum `mu = SQRT(n(n+2)) = sqrt(3(3+2)) = 3.87BM`


Discussion

No Comment Found

Related InterviewSolutions