1.

Calculate spin magnetic momentum of M_((aq))^(+2) ions. (Z=26)

Answer»

4.89 BM
0.489BM
48.9BM
489BM

Solution :Here, atomic number Z=26
So, for M ions `= [Ar] 3d^(6) 4S^(2)`
So, for `M^(+2)` ions `= [Ar] 3d^(6) 4s^(0)`

Here, UNPAIRED ELECTRONS are 4.
`:.` Magnetic momentum `mu= SQRT(n(n+2))`
`=sqrt(4(4+2)) = 4.89BM`


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