1.

Calculate relative rate of effusion of O_(2) to CH_(4) through a container containing O_(2) and CH_(4) in 3:2 mass ratio:

Answer»

`(3sqrt(2))/(4)`
`(3sqrt(2))/(8)`
`(3)/(2sqrt(2))`
`(3sqrt(2))/(2)`

SOLUTION :`(r_(o_(2)))/(r_(CH_(4)))=(n_(o_(2)))/(n_(CH_(4)))=sqrt((M_(CH_(4)))/(M_(O_(2))))`
`=(3)/((2)/(2))=sqrt((16)/(32))`
`=(3)/(4sqrt(2))`


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