1.

Calculate Q value of the following nuclear reaction 13^(Al^(27)) + 2^(He^(4)) rarr 14^(Si^(30)) + 1^(H^(1))+ Q. The exact mass of 13^(Al^(27)) is 26.9815 amu, 14A^(Si^(30)) is 29.9738, 2^(He^(4)) is 4.0026 amu and 1^(H^(1)) is 1.0078 amu.

Answer»

Solution :`triangle m`=(29.9738+1.0078)-(26.9815+4.0026)
=00.0025 amu
Q =0.0025 xx 931 MEV
=2.329 MeV


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