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Calculate PH and p o h of 10^-8 M HCL solution |
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Answer» Explanation: [H+] = 10‐⁸ M As we can SEE, The concentration of H+ is very low. Hence, It is a very DILUTE solution. So, we have to consider Concentration of H+ from H2O also. [H+] of water = 10‐⁷ M Total [H+] = (10‐⁸ + 10‐⁷ ) M ~ 10‐⁷ (APPROX.) pH = -log[H+] = 7 (approx.) pOH = 14 - pH = 14 - 7 = 7 (approx.) |
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