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Calculate number of moles and molecules of ammonia ( NH3 ) gas in volume of 67. 8 dm3 at STP write the value of Avogadro's number |
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Answer» NH3=67.2dm^3 NH3=67.2dm^3No. Of moles = 67.2 ÷ MOLAR volume NH3=67.2dm^3No. Of moles = 67.2 ÷ molar volumeof gas NH3=67.2dm^3No. Of moles = 67.2 ÷ molar volumeof gas=67.2÷22.4 NH3=67.2dm^3No. Of moles = 67.2 ÷ molar volumeof gas=67.2÷22.4=3.0 mol NH3=67.2dm^3No. Of moles = 67.2 ÷ molar volumeof gas=67.2÷22.4=3.0 molNo. of = 3.0 × avocadro's constant NH3=67.2dm^3No. Of moles = 67.2 ÷ molar volumeof gas=67.2÷22.4=3.0 molNo. of = 3.0 × avocadro's constantmolecule. = 3.0 × 6.022 × 10^23 NH3=67.2dm^3No. Of moles = 67.2 ÷ molar volumeof gas=67.2÷22.4=3.0 molNo. of = 3.0 × avocadro's constantmolecule. = 3.0 × 6.022 × 10^23= 18.066 × 10^23 molecules Hope it helps you... PLZ MARK ME AS A BRAINLIEST!!! |
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