Calculate number of atoms in: (Atomic masses: N=14u, H=1u)(i) 100 g of

1.	Calculate number of atoms in: (Atomic masses: N=14u, H=1u)(i) 100 g of nitrogen gas
Answer» Answer: 2.15 X $10^{24}$ EXPLANATION: Mass of Nitrogen GAS( $N_{2}$ ) = 100g Molar mass of Nitrogen gas( $N_{2}$ ) = 2 x 14 = 28g/mol No. of moles in $N_{2}$ gas = 100/28 = 3.57 moles No. of atoms = 3.57 x $N_{A}$ where $N_{A}$ is AVOGADRO number = 3.57 x 6.022 x $10^{23}$ = 21.5 x $10^{23}$ = 2.15 x $10^{24}$