1.

Calculate molality of a solution containing 2.5g of ethanoic acid in 75g of benzene

Answer»

Molality=no. of MOLES of SOLUTE/weight of solvent
no. of moles of solute= 2.5/60=25/600
=1/24=0.04mol
molality=0.04×1000/75=0.53 mol/g


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