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Calculate mean deviation from the median of the following data:Class interval:0-66-1212-1818-2424-30Frequency45362 |
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Answer» First we have to construct a table for the given data. Please refer to video for creating complete table. Here, `N = sum f_i = 20` `:. N/2 = 20/2 = 10` So, median class will be `6-12`. Now, Median, `M = l+((N/2 -c.f.)/f)**h` Here, `l` = lower limit of median class = `12` `N` = Total frequency = `20` `c.f.` = Cumulative frequency of pre median class` = 9` `f` = Frequency of median class = `3` `h` = Class size `= 6` `:. Median = 12+((10-9)/3)**6 = 12+2 = 14` Now, we will find the deviation from the median of the mid value of each class. `:. |d_i| =11,5,1,7,13` `:. f_i d_i = 44,25,3,42,26` `:. sum f_i d_i = 140` `:.` Mean deviation `= ( sum f_i d_i )/N = 140/20 = 7.` |
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