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Calculate mass % of solution prepared using 12g NaOH & 90g water Also calculate its molality​

Answer» MASS %= 12/102×100 = 11.8 %no. of mole NaOH = 12/ MOLARS mass= 0.3molality= mole of solute/ mass of solutions in KG = 0.3/0.09(kg) = 33.3 m


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