Calculate magnetic moment of Fe^(+3) ions. (Fe= 26) – InterviewSolution

1.	Calculate magnetic moment of Fe^(+3) ions. (Fe= 26)
Answer» 5.9BM 0.59BM 59 BM 590BM Solution :ELECTRONIC configuration of `FE^(+3) = [Ar] 3d^(5) 4s^(0)` So, d-orbital here, 5 unpaired ELECTRONS are PRESENT in d-orbitals so, magnetic momentum `mu = sqrt(n(n+2))` `=sqrt(5(5+2))= 5.9BM`

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