Calculate magnetic moment fe2+ion z=26

1.	Calculate magnetic moment fe2+ion z=26
Answer» Answer: 4.9 BM Explanation: ELECTRONIC CONFIGURATION of Fe with atomic number = 26 $Fe:26:[Ar]3d^64s^2$ $Fe^{2+}:23:[Ar]3d^6$ The number of unpaired electrons in $Fe^{2+}$ is 4 Formula used for magnetic MOMENT : $\mu=\sqrt{n(n+2)}$ where, $\mu$ = magnetic moment n = number of unpaired electrons Now put all the given values in the above formula, we get the magnetic moment. $\mu=\sqrt{4(4+2)}=4.9BM$ Therefore, the magnetic moment is 4.9 BM

Answer»

Answer: 4.9 BM

Explanation:

ELECTRONIC CONFIGURATION of Fe with atomic number = 26

$Fe:26:[Ar]3d^64s^2$