1.

Calculate Lamda_(m)^(@) for CaCl_(2) and MgSO_(4): Value of lamda_(m)^(@):

Answer»

Solution :We know from Kohlrausch law that: Limiting molar CONDUCTIVITY of electrolyte=sum of limiting molar conductivity of IONS present in it.
(i) Calculation for limiting molar conductivity of `CaCl_(2)`:
`CaCl_(2)toCa_((aq))^(2+)+2Cl_((aq))^(-)`
`therefore Lamda_(m)^(@)(CalCl_(2))=lamda_(m)^(@)(Ca^(2+))+2lamda_(m)^(@)(Cl^(-))`
`=[119.0+2(76.3)]" S "cm^(2)mol^(-1)`
`=(119.0+152.6)"S "cm^(2)mol^(-1)`
`=271.6" S "cm^(2)mol^(-1)`
(ii) Calculation for limiting molar conductivity of `MgSO_(4):`
`therefore Lamda_(m)^(@)(MgSO_(4))=lamda_(m)^(@)(MG^(2+))+lamda_(m)^(@)(SO_(4)^(2-))`
`=[106.0+160]" S "cm^(2)mol^(-1)`
`=266.0" S "cm^(2)mol^(-1)`


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