Calculate ionic strength of 0.15molal kcl solution

1.	Calculate ionic strength of 0.15molal kcl solution
Answer» ANSWER: 1. I=\frac{1}{2}\sum ^{n}_{i=1}c_{i}Z^{2}_{i} 2. Here, half the term ½ is because we consider both the IONS as cation and anion. ... 3. Answer- FIRST of all, the dissociation will be KCL\rightarrow K^{+}+Cl^{-}.

Answer»

1. I=\frac{1}{2}\sum ^{n}_{i=1}c_{i}Z^{2}_{i}

2. Here, half the term ½ is because we consider both the IONS as cation and anion. ...

3. Answer- FIRST of all, the dissociation will be KCL\rightarrow K^{+}+Cl^{-}.

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