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Calculate [H^(+)] in a 0.20M solution of dichloriacetic acid (K_(a)=5xx10^(-2)) that also contains 0.1M sodium dichloroacetate.Neglect hydrolysis of sodium salt.

Answer»

Solution :`{:(,CHCl_(2)COOHhArr,CHCl_(2)COO^(-),+,H^(+)),("Before diassociation",0.2,-,,-),("After DISSOCIATION",(0.2-x),x,,x),(,CHCl_(2)COONararr,CHCl_(2)COO^(-),+,Na^(+)),(,,0.1,,0.1):}`
for the dissociation of acid
`K_(a)=5xx10^(-2)=([CHCl_(2)COOH^(-)][H^(+)])/([CHCH_(2)COOH])or 0.05=([0.1+x][x])/([0.2-x])`
`x=0.05` or `[H^(+)]=0.05M`


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