calculate following is 3.65 gram of HCL dissolve in 16.35 gram of wate

1.	calculate following is 3.65 gram of HCL dissolve in 16.35 gram of water and given solution of density 1.2 gram per ml then calculate percentage weight by weight 2nd % weight by volume and third mole fraction of both
Answer» Answer: Calculate the NUMBER of moles of solute present. Moles of NaOH = 15.0 g NaOH × 1 mol NaOH 40.00 g NaOH = 0.375 mol NaOH Calculate the number of LITRES of solution present. Volume = 225 ML × 1 L 1000 mL = 0.225 L soln Divide the number of moles of solute by the number of litres of solution. Molarity = 0.375 mol 0.225 L = 1.67 mol/L

calculate following is 3.65 gram of HCL dissolve in 16.35 gram of water and given solution of density 1.2 gram per ml then calculate percentage weight by weight 2nd % weight by volume and third mole fraction of both

Answer»

Answer:

Calculate the NUMBER of moles of solute present.

Moles of NaOH = 15.0 g NaOH ×

mol NaOH

40.00

g NaOH

= 0.375 mol NaOH

Calculate the number of LITRES of solution present.

Volume = 225 ML ×

1000

= 0.225 L soln

Divide the number of moles of solute by the number of litres of solution.

Molarity =

0.375

mol

0.225

= 1.67 mol/L