1.

Calculate equilibrium constant for I_(2)+I^(-) hArr I_(3)^(-) at 298 K from the following information : {:(I_(2) (aq.)+2e^(-) rarr 2I^(-),,E^(@)=0.6197" volt"),(I_(3)^(-)+2e^(-) rarr 3I^(-),,E^(@)=0.5355" volt"):}

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Solution :`{:(I_(2)+2E^(-) RARR 2I^(-),""E^(@)=0.6197" volt"),(3I^(-) rarr I_(3)^(-)+2e^(-)," "E^(@)=-0.5355" volt"),(bar(I_(2)+I^(-) HARR I_(3)^(-),)""E^(@)=0.6197-0.5355),(""=0.0842" volt"):}`
`K="antilog" [(NE^(@))/0.0591]="antilog"[(2xx0.0842)/0.0591]=706.9`


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